[Physics] About "logical errors"

carmam at tiscali.co.uk carmam at tiscali.co.uk
Thu Nov 10 13:56:18 CET 2016


I found this in my draft box, and probably did not send it. Apologies if  I did and it is a duplicate.
Mike, Please read "Relativity The Special And The General Theory" by A Einstein, published by Methuen & co 1920 (my issue was printed 1962, but is substantially the same). I have not provided any input for why the room is being accelerated for the simple reason is that it does not matter one iota (see chapter XX). It is clear to me that you are a mathematician, the way you dive into maths at the earliest opportunity. For the most part, I speak in plain language that can be understood by the layman. I said that my reply would be in two parts, please answer the question posed and then we can move onto part 2.Tom.



----Original Message----

From: mike at mlawrence.co.uk

Date: 05/11/2016 21:21

To: "General Physics and Natural Philosophy discussion list"<physics at tuks.nl>

Subj: Re: [Physics] About "logical errors"

On Nov 5 2016, carmam at tiscali.co.uk wrote: 
Mike, there are two answers to your refutation of my equivalence principle argument. 



1. I started out with the very simple case of an MBH being dropped from 20 metres above the Earth's surface. The total gravitational attraction is now 19.6 M/s^2 and the black hole will reach the surface in 1.4s . True or false?If the MBH is dropped from 20 metres in a "room" which is being accelerated at 9.8M/s^2 , it will hit the floor after 2s . True or false?We have to make some assumptions here. A. The accelerated room is being held at a steady  9.8M/s^2 , no matter what mass it contains.B. The fall is timed from the reference frame of the Earth or the accelerated room.C. There are no external influences. This includes nothing influencing the clock eg it is far enough away from the MBH. D. The gravitational attraction of the MBH is 9.8 M/s^2 at 20 metres, I am ignoring the increase as the two masses approach.Please respond before we move to the second part.

Tom.
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