[Physics] Shadow Gravity and Spiral Galaxies

[mikelawr at freenetname.co.uk]

Arend,

Thanks for the discussion of G again, but G is a dimesionless constant. 
Either see the attached published paper or simply substitute [(sqrt G) x 
M] = m for mass and [R/(sqrt G)] = r for distance in any equation of 
mass-related motion, energy or force and you will find G disappears. 
Here it is for orbital forces:

     F  = GMM/R^2 = Mv^2 /R  = [(sqrt G)M]^2/G[R/(sqrt G)]^2 = [(sqrt G) 
x M] v^2 /G[R/(sqrt G)]

        =  m^2/Gr^2  =  m v^2 /Gr

so  F  = m^2/r^2  = m v^2 /r

QED  - No G.

The point is that to eliminae G requires recognising that it needs to be 
taken out of both the mass and distance parameters. It is not a 
gravitational-alone factor. Once you have done this, you an check that G 
is actually dimensionless, like h. Past efforts at eliminating G have 
foundered on only trying to include it with the mass parameter.

The paper shows that SI units actually hide that the strength of mass 
and charge fields are the same at the fundamental level. Why they appear 
different is because charge is generated as a function of the Planck 
charge on the Planck sized fundamental particle/anti-particles whereas 
the masses we see are based on the sizes (rotational frequencies) of the 
loops - which comprise our fermions.

Cheers
Mike

On 2020-04-30 06:06, Arend Lammertink wrote:
> Hi all,
> 
> Paul sent me some interesting (draft) stuff about shadow gravity and
> spiral galaxies in august/september last year:
> 
> -:-
> I am including below the progress I've made in the recent past.  First
> I've found an expression the given us the gravitational constant.
> 
> G = ([4π]c/q)(2a^2c/A)^2 = 6.665E-11         m^3/kg-sec^2
> Where a = Sqrt(3)8pi^2
>       A = Avogadro Number  = 6.02214129E+23
>       q = Elemental Charge = 1.60403E-19    kg/sec
>       c = Light Speed      = 2.9979E+08      m/sec
> G = h'c(8π/mₑN')² = 6.673274E-11  Verses CODATA Concise form  
> 6.67384E-11
> h' = h-bar          (1.05457E-34)
> c = Light Speed     (2.99792E+08)
> mₑ= Electron Mass   (9.10938E-31)
> N'= Avrogadro Prime (5.97864E+23) = 6.02214E+23((1.66054 / 1.67262)
> 
> Not sure how it all fits in yet but the Coulomb constant can also be
> expressed in terms of h'c so yes, gravity is a second order effect of
> EM.  I also realized that Shadow Gravity must weaken as it passes
> through multiple bodies.  I am in the early stages of writing this up
> an am attaching the very first draft writeup and would be interested
> in your take & comments.
> -:-
> 
> -:-
> I am including an analysis of the cumulative shadowing effects of a
> flat spiral galaxy and what the Shadow (LeSagian) Gravity orbital
> dynamics process produces as a result.  I will also include a graphic
> plot of actual observations.
> -:-
> 
> Appears to be helpful in your discussion.
> 
> All the best,
> 
> Arend.
> 
> 
> 
> On Wed, Apr 29, 2020 at 3:17 PM Tom Hollings <carmam at tiscali.co.uk> 
> wrote:
>> 
>> Got it that time Mike, thanks. The slow rotation rate makes it 
>> difficult to estimate the speed in any case, but point taken.
>> Tom.
>> 
>> 
>> > On 29 April 2020 at 12:54 mikelawr at freenetname.co.uk wrote:
>> >
>> >
>> > Tom
>> >
>> > I said the rotational rates would not be dfferent. What will be
>> > different is the actual velocities of the arms because you need to
>> > separate out the viscosity red shift of the centre and arms, which will
>> > be the same because they are the same distance from us, from the local
>> > reference frame where the centre and arms will be different.
>> > Unfortunately we don't know what the value of any viscosity red shift is
>> > yet. Because the galaxy as a whole may be closer to us, then the
>> > distance from centre to arms will be different to that which we
>> > currently think it is. So with a different radius, but same rotational
>> > frequency, then the estimaed velocity of the arms will be lower.
>> > Cheers
>> > Mike
>> 
>> _______________________________________________
>> Physics mailing list
>> Physics at tuks.nl
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