Olivier, you are quite correct in pointing out that the gravitational attraction at the distance of 6,371,020 metres is so small, I did miss that. Thank you. I didn't even see it when I first read your message, I had to read it a couple of times before it dawned on me, I should have realised there weren't enough zeros. Mea Culpa.<div><div><br>Tom.</div><div><br></div><div><br>
----Original Message----<br>
From: o.serret@free.fr<br>
Date: 08/11/2016 20:09<br>
To: <physics@tuks.nl><br>
Subj: Re: [Physics] About the equivalence principle<br>
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<div style="FONT-SIZE: 12pt; FONT-FAMILY: 'Calibri'; COLOR: #000000">
<div>Hello Tom,</div>
<div> </div>
<div>Thank you for your explanation.</div>
<div> </div>
<div>I think there is a little mistake in your calculation :</div>
<div> </div>
<div>you write : </div>
<div>> <span style="font-family: 'Courier New';">The acceleration which an object of mass =
100Kg imparts to another mass at 20 metres is :-a = 6.674e-11 * 100 / 20^2 =
0.000000000016685 M/s^2</span></div>
<div><span style="font-family: Calibri;"></span> </div>
<div><span style="font-family: Calibri;">In the case of an object, 100
kg for example, at 20 m from the SURFACE of the Earth, calculation of
acceleration should be calculated from both CENTERS OF
GRAVITY:</span></div>
<div>a = 6.674e-11 * 100 / (<span style="font-size: 18pt;">6371020</span>+20) ^2 = 0.<span style="font-size: 18pt;">00000000000</span>000000000016 M/s^2</div>
<div> </div>
<div><span style="font-family: 'Courier New';"></span> </div>
<div><span style="font-family: Calibri;">It should not change your
conclusion, and even enhance it !!!</span></div>
<div> </div>
<div>Do you agree with my comment ?</div>
<div> </div>
<div>Best regards</div>
<div>Olivier</div></div></div>
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