<div dir="ltr">Hello Arend and others.<div>I saw that the images for the equations in my response are missing. If you want to read my response again with included equations, please follow this link:<div><a href="https://bit.ly/2SsDMZu">https://bit.ly/2SsDMZu</a> <br></div></div><div><br></div><div>Best regards.</div><div>Ruud Loeffen.</div></div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">Op vr 1 mei 2020 om 11:44 schreef Ruud Loeffen <<a href="mailto:rmmloeffen@gmail.com">rmmloeffen@gmail.com</a>>:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex"><div dir="ltr"><div dir="ltr"><div>Hello Arend.</div><div><br></div><div>The file "Shadow Gravity" inspires me to present some thoughts that I have inserted below.</div><div><br></div><div>Best regards.<br>Ruud Loeffen</div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">Op do 30 apr. 2020 om 13:10 schreef Arend Lammertink <<a href="mailto:lamare@gmail.com" target="_blank">lamare@gmail.com</a>>:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex">Hi all,<br>
<br>
Paul sent me some interesting (draft) stuff about shadow gravity and<br>
spiral galaxies in august/september last year:<br>
<br>
-:-<br>
I am including below the progress I've made in the recent past. First<br>
I've found an expression the given us the gravitational constant.<br>
<br>
G = ([4π]c/q)(2a^2c/A)^2 = 6.665E-11 m^3/kg-sec^2<br>
Where a = Sqrt(3)8pi^2<br>
A = Avogadro Number = 6.02214129E+23<br>
q = Elemental Charge = 1.60403E-19 kg/sec<br>
c = Light Speed = 2.9979E+08 m/sec<br>
G = h'c(8π/mₑN')² = 6.673274E-11 Verses CODATA Concise form 6.67384E-11<br>
h' = h-bar (1.05457E-34)<br>
c = Light Speed (2.99792E+08)<br>
mₑ= Electron Mass (9.10938E-31)<br>
N'= Avrogadro Prime (5.97864E+23) = 6.02214E+23((1.66054 / 1.67262)<br>
<br>
Not sure how it all fits in yet but the Coulomb constant can also be<br>
expressed in terms of h'c so yes, gravity is a second order effect of<br>
EM. I also realized that Shadow Gravity must weaken as it passes<br>
through multiple bodies. I am in the early stages of writing this up<br>
an am attaching the very first draft writeup and would be interested<br>
in your take & comments.<br></blockquote><div><font color="#0000ff"> Do you remember the equation that Jesus Sanches presented a year ago, or so,:</font><br><div><img alt="image.png" width="484" height="78"><br></div><font color="#0000ff">I think that it is possible to construct many different equations that result in the Gravitational Constant with the correct units ( m^3 / kg.s^2 ) using a combination of the hundreds of constants that are in use at the moment. I don't know if your equation or the one of Jesus makes any sense. The question is: do you have an explication for that equation: What Does It Mean?<br>I got a more simple expression of the Gravitational Constant as the one you present here. </font> <font color="#0000ff"><br></font></div><div><font color="#0000ff">Some weeks ago I presented "The Splitted Gravitational Constant" in a short video</font> <b style="font-family:Calibri,sans-serif;color:blue"><span lang="EN-US" style="line-height:107%;color:rgb(0,176,80)"><a href="http://bit.ly/2SPWfzH" style="color:blue" target="_blank"><font size="4">Splitting the Gravitational Constant</font></a> </span></b><span lang="EN-US" style="font-family:Calibri,sans-serif;font-size:11pt;color:blue"><a href="http://bit.ly/2SPWfzH" style="font-size:11pt;color:blue" target="_blank">http://bit.ly/2SPWfzH</a></span></div><div><font color="#0000ff">G = (0.5 c^2/4<span style="font-family:Calibri,sans-serif;font-size:11pt">π) * "kappa"</span></font></div><div><font color="#0000ff"><span style="font-family:Calibri,sans-serif;font-size:11pt">For "kappa" I take the Einsteinian Coupling Constant from his paper "</span><span lang="EN-US" style="font-size:9pt;line-height:107%;font-family:Arial,sans-serif">The
principle of relativity, A collection of original papers “</span><span lang="EN-US" style="font-size:10pt;line-height:107%;font-family:Arial,sans-serif">On the special and general theory of relativity” 1915 " with the form: K = 8*
π
G / c^2</span></font></div><div><span lang="EN-US" style="line-height:107%"><span style="font-family:Arial,sans-serif;font-size:10pt"><font color="#0000ff">I rearranged this equation to:</font></span><br><div style="font-family:Arial,sans-serif;color:rgb(0,176,80);font-size:10pt"><img alt="image.png" width="475" height="181"><br></div><div style="font-family:Arial,sans-serif;font-size:10pt"><font color="#0000ff">This leads to the calculation of the acceleration at the surface of a planet.</font><br><div style="color:rgb(0,176,80)"><img alt="image.png" width="275" height="68"><br></div><font color="#00b050"> For the earth:</font><br><br></div><div style="font-family:Arial,sans-serif;color:rgb(0,176,80);font-size:10pt"><img alt="image.png" width="475" height="55"><br></div><div style="font-family:Arial,sans-serif;color:rgb(0,176,80)"><span style="font-size:10pt">In my book </span><b style="font-family:Arial,Helvetica,sans-serif;color:blue"><span lang="EN-US" style="line-height:107%;font-family:Calibri,sans-serif;color:rgb(0,176,80)"><a href="http://bit.ly/2CFGDIh" style="font-family:Arial,Helvetica,sans-serif;color:blue" target="_blank">CON-FUSING GRAVITATION.
Applying the Lorentz Transformation of Mass-Energy</a> </span></b><span lang="EN-US" style="font-family:Calibri,sans-serif;color:blue;font-size:11pt;line-height:107%"><a href="http://bit.ly/2CFGDIh" style="font-family:Arial,Helvetica,sans-serif;color:blue" target="_blank">http://bit.ly/2CFGDIh</a></span></div><div><font color="#0000ff"><font face="Arial, sans-serif">I explained the possible meaning of the equation as an INFLUX of the energy-field </font></font>(0.5 m.c^2) <span style="font-family:Arial,sans-serif;color:rgb(0,0,255)"> towards the </span><span style="font-family:Arial,sans-serif;color:rgb(0,0,255)">center</span><span style="font-family:Arial,sans-serif;color:rgb(0,0,255)"> of mass in chapter: The falling stone. Splitting the Gravitational Constant.</span></div><div style="font-family:Arial,sans-serif"><font color="#0000ff">At this point there might be a connection with more complicated formats for the Gravitational Constant as the one Arend presents here or Jesus Sanches. MAYBE, THERE ARE OTHER FORMATS RELATED TO AN INFLUX OF ENERGY TO THE CENTER. </font><font color="#9900ff">So, I am searching for other contributions that support my interpretation.</font></div><div><font color="#0000ff"><font face="Arial, sans-serif">The "kappa" function expresses a tiny expansion of the earth as seen in earthquakes, volcano's. drifting continents.</font></font></div><div><font color="#0000ff"><font face="Arial, sans-serif">I know my equation of the Splitted Gravitational Constant is very simple, but it is in accordance with Einsteins equation, the results of the calculations are clear and correct without any doubt and there is a possible explanation, that fits with many arising theories about the INFLUX of an ETHER.</font></font></div><div><font color="#0000ff"><font face="Arial, sans-serif">So, I hope you will view my video: </font></font><a href="http://bit.ly/2SPWfzH" target="_blank">http://bit.ly/2SPWfzH</a><br> </div><div><font color="#0000ff"><font face="Arial, sans-serif">Please like it, if you like it.</font></font></div><div><font color="#0000ff" face="Arial, sans-serif">Best regards. Ruud Loeffen.</font></div></span></div></div></div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">Op do 30 apr. 2020 om 13:10 schreef Arend Lammertink <<a href="mailto:lamare@gmail.com" target="_blank">lamare@gmail.com</a>>:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex">Hi all,<br>
<br>
Paul sent me some interesting (draft) stuff about shadow gravity and<br>
spiral galaxies in august/september last year:<br>
<br>
-:-<br>
I am including below the progress I've made in the recent past. First<br>
I've found an expression the given us the gravitational constant.<br>
<br>
G = ([4π]c/q)(2a^2c/A)^2 = 6.665E-11 m^3/kg-sec^2<br>
Where a = Sqrt(3)8pi^2<br>
A = Avogadro Number = 6.02214129E+23<br>
q = Elemental Charge = 1.60403E-19 kg/sec<br>
c = Light Speed = 2.9979E+08 m/sec<br>
G = h'c(8π/mₑN')² = 6.673274E-11 Verses CODATA Concise form 6.67384E-11<br>
h' = h-bar (1.05457E-34)<br>
c = Light Speed (2.99792E+08)<br>
mₑ= Electron Mass (9.10938E-31)<br>
N'= Avrogadro Prime (5.97864E+23) = 6.02214E+23((1.66054 / 1.67262)<br>
<br>
Not sure how it all fits in yet but the Coulomb constant can also be<br>
expressed in terms of h'c so yes, gravity is a second order effect of<br>
EM. I also realized that Shadow Gravity must weaken as it passes<br>
through multiple bodies. I am in the early stages of writing this up<br>
an am attaching the very first draft writeup and would be interested<br>
in your take & comments.<br>
-:-<br>
<br>
-:-<br>
I am including an analysis of the cumulative shadowing effects of a<br>
flat spiral galaxy and what the Shadow (LeSagian) Gravity orbital<br>
dynamics process produces as a result. I will also include a graphic<br>
plot of actual observations.<br>
-:-<br>
<br>
Appears to be helpful in your discussion.<br>
<br>
All the best,<br>
<br>
Arend.<br>
<br>
<br>
<br>
On Wed, Apr 29, 2020 at 3:17 PM Tom Hollings <<a href="mailto:carmam@tiscali.co.uk" target="_blank">carmam@tiscali.co.uk</a>> wrote:<br>
><br>
> Got it that time Mike, thanks. The slow rotation rate makes it difficult to estimate the speed in any case, but point taken.<br>
> Tom.<br>
><br>
><br>
> > On 29 April 2020 at 12:54 <a href="mailto:mikelawr@freenetname.co.uk" target="_blank">mikelawr@freenetname.co.uk</a> wrote:<br>
> ><br>
> ><br>
> > Tom<br>
> ><br>
> > I said the rotational rates would not be dfferent. What will be<br>
> > different is the actual velocities of the arms because you need to<br>
> > separate out the viscosity red shift of the centre and arms, which will<br>
> > be the same because they are the same distance from us, from the local<br>
> > reference frame where the centre and arms will be different.<br>
> > Unfortunately we don't know what the value of any viscosity red shift is<br>
> > yet. Because the galaxy as a whole may be closer to us, then the<br>
> > distance from centre to arms will be different to that which we<br>
> > currently think it is. So with a different radius, but same rotational<br>
> > frequency, then the estimaed velocity of the arms will be lower.<br>
> > Cheers<br>
> > Mike<br>
><br>
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</blockquote></div><br clear="all"><div><br></div>-- <br><div dir="ltr"><div dir="ltr"><div><div dir="ltr"><div dir="ltr"><font face="comic sans ms, sans-serif" size="2"><b>Ruud Loeffen</b></font><div><a href="http://www.human-DNA.org" style="font-size:12.8px" target="_blank">http://www.human-DNA.org</a><br></div></div></div></div></div></div></div>
</blockquote></div><br clear="all"><div><br></div>-- <br><div dir="ltr" class="gmail_signature"><div dir="ltr"><div><div dir="ltr"><div dir="ltr"><font face="comic sans ms, sans-serif" size="2"><b>Ruud Loeffen</b></font><div><a href="http://www.human-DNA.org" style="font-size:12.8px" target="_blank">http://www.human-DNA.org</a><br></div></div></div></div></div></div>