[Physics] About the equivalence principle
O. Serret
o.serret at free.fr
Tue Nov 8 21:09:07 CET 2016
Hello Tom,
Thank you for your explanation.
I think there is a little mistake in your calculation :
you write :
> The acceleration which an object of mass = 100Kg imparts to another mass at 20 metres is :-a = 6.674e-11 * 100 / 20^2 = 0.000000000016685 M/s^2
In the case of an object, 100 kg for example, at 20 m from the SURFACE of the Earth, calculation of acceleration should be calculated from both CENTERS OF GRAVITY:
a = 6.674e-11 * 100 / (6371020+20) ^2 = 0.00000000000000000000016 M/s^2
It should not change your conclusion, and even enhance it !!!
Do you agree with my comment ?
Best regards
Olivier
-------------- section suivante --------------
Une pi?ce jointe HTML a ?t? nettoy?e...
URL: <http://mail.tuks.nl/pipermail/physics/attachments/20161108/176e2b60/attachment.html>
More information about the Physics
mailing list