[Physics] About the equivalence principle

O. Serret o.serret at free.fr
Tue Nov 8 21:09:07 CET 2016


Hello Tom,

Thank you for your explanation.

I think there is a little mistake in your calculation :

you write : 
> The acceleration which an object of mass = 100Kg imparts to another mass at 20 metres is :-a = 6.674e-11 * 100 / 20^2 = 0.000000000016685 M/s^2

In the case of an object, 100 kg for example, at 20 m from the SURFACE of the Earth, calculation of acceleration should be calculated from both CENTERS OF GRAVITY:
a = 6.674e-11 * 100 / (6371020+20) ^2 = 0.00000000000000000000016 M/s^2


It should not change your conclusion, and even enhance it !!!

Do you agree with my comment ?

Best regards
Olivier
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