[Physics] About the equivalence principle

[carmam at tiscali.co.uk]

Olivier, you are quite correct in pointing out that the gravitational attraction at the distance of 6,371,020 metres is so small, I did miss that. Thank you. I didn't even see it when I first read your message, I had to read it a couple of times before it dawned on me, I should have realised there weren't enough zeros. Mea Culpa.
Tom.


----Original Message----

From: o.serret at free.fr

Date: 08/11/2016 20:09

To: <physics at tuks.nl>

Subj: Re: [Physics] About the equivalence principle







Hello Tom,
 
Thank you for your explanation.
 
I think there is a little mistake in your calculation :
 
you write : 
> The acceleration which an object of mass = 
100Kg imparts to another mass at 20 metres is :-a = 6.674e-11 * 100 / 20^2 = 
0.000000000016685 M/s^2
 
In the case of an object, 100 
kg for example, at 20 m from the SURFACE of the Earth, calculation of 
acceleration should be calculated from both CENTERS OF 
GRAVITY:
a = 6.674e-11 * 100 / (6371020+20) ^2 = 0.00000000000000000000016 M/s^2
 
 
It should not change your 
conclusion, and even enhance it !!!
 
Do you agree with my comment ?
 
Best regards
Olivier
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